What would be the SI unit for the quantity fr | vedclass

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(A) The $SI$ unit for pressure,$p$ is $N \ m^{-2}$.The $SI$ unit for volume,$V$ is $m^{3}$.The $SI$ unit for temperature,$T$ is $K$.The $SI$ unit for

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$N \ m^{4} \ K^{2} \ mol^{-1}$

Vedclass · Answer

(A) The $SI$ unit for pressure,$p$ is $N \ m^{-2}$.The $SI$ unit for volume,$V$ is $m^{3}$.The $SI$ unit for temperature,$T$ is $K$.The $SI$ unit for the number of moles,$n$ is $mol$.Therefore,the $SI$ unit for the quantity $\frac{p V^{2} T^{2}}{n}$ is calculated as:$= \frac{(N \ m^{-2}) 	imes (m^{3})^{2} 	imes (K)^{2}}{mol}$$= \frac{N \ m^{-2} 	imes m^{6} 	imes K^{2}}{mol}$$= N \ m^{4} \ K^{2} \ mol^{-1}$

What would be the $SI$ unit for the quantity $\frac{p V^{2} T^{2}}{n}$?

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