When PbO_2 reacts with conc. HNO_3,the gas ev | vedclass

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Question

(B) The reaction between lead$(IV)$ oxide $(PbO_2)$ and concentrated nitric acid $(HNO_3)$ is an oxidation-reduction reaction.$PbO_2$ acts as an oxidi

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$O_2$

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(B) The reaction between lead$(IV)$ oxide $(PbO_2)$ and concentrated nitric acid $(HNO_3)$ is an oxidation-reduction reaction.$PbO_2$ acts as an oxidizing agent and oxidizes water to oxygen gas.The balanced chemical equation is:$PbO_2 + 2HNO_3 \rightarrow Pb(NO_3)_2 + H_2O + \frac{1}{2} O_2$Thus,the gas evolved is oxygen $(O_2)$.

When $PbO_2$ reacts with conc. $HNO_3$,the gas evolved is:

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