When $B_2H_6$ reacts with excess $NH_3$ at a very high temperature $(> 200 \, ^\circ C)$,the product formed is:
- A$[BH_2(NH_3)_2]^+ [BH_4]^-$
- B$(BN)_x$
- C$B_3N_3H_6$
- DNone
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Similar Questions
Match the following compounds in List-$I$ with their uses in List-$II$:
List-$I$ (Compounds) List-$II$ (Uses) $A$. Boron-$10$ $I$. Antiseptic $B$. Borax $II$. Bullet proof vest $C$. Boron-fibre $III$. Neutron absorber $D$. Orthoboric acid $IV$. Heat resistance glasses
| List-$I$ (Compounds) | List-$II$ (Uses) |
| $A$. Boron-$10$ | $I$. Antiseptic |
| $B$. Borax | $II$. Bullet proof vest |
| $C$. Boron-fibre | $III$. Neutron absorber |
| $D$. Orthoboric acid | $IV$. Heat resistance glasses |
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