When CuSO_4 is added to a solution of ammonia | vedclass

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(B) When $CuSO_4$ is added to an aqueous ammonia solution,it forms a complex ion $[Cu(NH_3)_4]^{2+}$.This reaction reduces the total number of solute

Vedclass · Accepted Answer

Freezing point is raised

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(B) When $CuSO_4$ is added to an aqueous ammonia solution,it forms a complex ion $[Cu(NH_3)_4]^{2+}$.This reaction reduces the total number of solute particles in the solution.According to colligative properties,the depression in freezing point $(\Delta T_f = i 	imes K_f 	imes m)$ and elevation in boiling point $(\Delta T_b = i 	imes K_b 	imes m)$ are directly proportional to the van 't Hoff factor $(i)$.Since the number of particles decreases,the van 't Hoff factor $(i)$ decreases.Consequently,the freezing point of the solution increases (less depression) and the boiling point decreases (less elevation).

Column-$I$	Column-$II$
$A$. Beckmann method	$1$. Osmotic pressure
$B$. Ostwald-Walker method	$2$. Elevation in $B$.$P$.
$C$. Berkeley-Hartley method	$3$. Depression in $F$.$P$.
$D$. Landsberger method	$4$. Relative lowering of vapour pressure

When $CuSO_4$ is added to a solution of ammonia,what happens to the boiling point and freezing point of the solution?

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