When HgI_2 is added to an aqueous solution of | vedclass

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(A) The chemical reaction is $HgI_2 + 2KI 	o K_2[HgI_4]$.In this reaction,the number of solute particles in the solution decreases because $3$ moles

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Freezing point is raised

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(A) The chemical reaction is $HgI_2 + 2KI 	o K_2[HgI_4]$.In this reaction,the number of solute particles in the solution decreases because $3$ moles of ions ($2K^+ + 2I^- + HgI_2$ complex formation) result in fewer effective particles in the form of the complex $K_2[HgI_4]$.According to the formula $\Delta T_f = i 	imes K_f 	imes m$,a decrease in the number of particles leads to a decrease in the depression of the freezing point $(\Delta T_f)$.Since the depression in freezing point decreases,the actual freezing point of the solution increases.

When $HgI_2$ is added to an aqueous solution of $KI$,then the:

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