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(D) The precipitation of metal sulfides in the presence of $HCl$ depends on the solubility product $(K_{sp})$ of the sulfides.$Cu^{2+}$,$Hg^{2+}$,and

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$CoS$

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(D) The precipitation of metal sulfides in the presence of $HCl$ depends on the solubility product $(K_{sp})$ of the sulfides.$Cu^{2+}$,$Hg^{2+}$,and $Bi^{3+}$ belong to Group-$II$ of the qualitative analysis scheme,where their sulfides ($CuS$,$HgS$,$Bi_2S_3$) have very low $K_{sp}$ values and precipitate in the presence of $H_2S$ and $HCl$.$Co^{2+}$ belongs to Group-$III$ (or $IV$ depending on the scheme),and its sulfide $(CoS)$ has a higher $K_{sp}$ compared to Group-$II$ sulfides.Therefore,$CoS$ does not precipitate in the acidic medium provided by $HCl$.

When $H_2S$ gas is passed through the $HCl$ containing aqueous solutions of $CuCl_2$,$HgCl_2$,$BiCl_3$ and $CoCl_2$,which does not precipitate out?

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