(B) The molar mass of water $(H_2O)$ is $18 \ g/mol$. Number of moles of water = $\frac{90 \ g}{18 \ g/mol} = 5 \ mol$. The molar mass of acetic acid

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(B) The molar mass of water $(H_2O)$ is $18 \ g/mol$. Number of moles of water = $\frac{90 \ g}{18 \ g/mol} = 5 \ mol$. The molar mass of acetic acid $(CH_3COOH)$ is $60 \ g/mol$. Number of moles of acetic acid = $\frac{300 \ g}{60 \ g/mol} = 5 \ mol$. Total number of moles = $5 \ mol + 5 \ mol = 10 \ mol$.