When H_2S gas is passed through a hot acidic | vedclass

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Question

(D) The correct answer is $D$. When $H_2S$ gas is passed through an acidic solution,only group $II$ cations precipitate as their sulfides because the

Vedclass · Accepted Answer

$PbS$ and $CuS$

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(D) The correct answer is $D$. When $H_2S$ gas is passed through an acidic solution,only group $II$ cations precipitate as their sulfides because the low concentration of $S^{2-}$ ions (due to the common ion effect of $H^+$) is sufficient to exceed the solubility product $(K_{sp})$ of group $II$ sulfides. Among the given ions,$Cu^{2+}$ and $Pb^{2+}$ belong to group $II$. $Al^{3+}$ belongs to group $III$ and $Ni^{2+}$ belongs to group $IV$,which do not precipitate in acidic medium. The reactions are: $Cu^{2+} + H_2S \longrightarrow CuS(s) + 2H^+$ $Pb^{2+} + H_2S \longrightarrow PbS(s) + 2H^+$

List-$I$ (Ion involved)	List-$II$ (Agent)
$(i) \, Ni^{2+}$	$(A).$ Sodium thiosulphate
$(ii) \, Ag^{+}$	$(B).$ Sodium nitroprusside
$(iii) \, Cu^{2+}$	$(C).$ Ammonia
$(iv) \, S^{2-}$	$(D).$ Dimethylglyoxime

When $H_2S$ gas is passed through a hot acidic aqueous solution containing $Al^{3+}$,$Cu^{2+}$,$Pb^{2+}$ and $Ni^{2+}$,a precipitate is formed,which consists of

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Match List-$I$ with List-$II$ and select the correct answer using the codes given below.

List-$I$ (Ion involved) List-$II$ (Agent)

$(i) \, Ni^{2+}$ $(A).$ Sodium thiosulphate

$(ii) \, Ag^{+}$ $(B).$ Sodium nitroprusside

$(iii) \, Cu^{2+}$ $(C).$ Ammonia

$(iv) \, S^{2-}$ $(D).$ Dimethylglyoxime

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