When $1-$chlorobutane is treated with aqueous $KOH$,it gives $P$. However,when it is treated with alcoholic $KOH$,it gives $Q$. Identify the products $P$ and $Q$ respectively.

• A
  $P = \text{butan-}1\text{-ol}, Q = \text{butan-}1\text{-ol}$
• B
  $P = \text{but-}1\text{-ene}, Q = \text{but-}2\text{-ene}$
• C
  $P = \text{but-}1\text{-ene}, Q = \text{butan-}1\text{-ol}$
• D
  $P = \text{butan-}1\text{-ol}, Q = \text{but-}1\text{-ene}$