When 10^{14} electrons are removed from a neu | vedclass

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Question

(A) The charge $Q$ on a body is given by the quantization of charge formula: $Q = ne$.Here,$n = 10^{14}$ is the number of electrons removed,and $e = 1

Vedclass · Accepted Answer

$16$

Vedclass · Answer

(A) The charge $Q$ on a body is given by the quantization of charge formula: $Q = ne$.Here,$n = 10^{14}$ is the number of electrons removed,and $e = 1.6 	imes 10^{-19} \ C$ is the elementary charge.Since electrons are removed from the neutral sphere,the sphere becomes positively charged.$Q = 10^{14} 	imes 1.6 	imes 10^{-19} \ C = 1.6 	imes 10^{-5} \ C$.To convert this into microcoulombs $(\mu C)$,we multiply by $10^6$:$Q = 1.6 	imes 10^{-5} 	imes 10^6 \ \mu C = 1.6 	imes 10^1 \ \mu C = 16 \ \mu C$.

When $10^{14}$ electrons are removed from a neutral metal sphere,the charge on the sphere becomes ...... $\mu C$.

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