When K_2O is added to water,the solution beco | vedclass

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(C) When $K_2O$ is added to water,it reacts to form potassium hydroxide: $K_2O + H_2O \rightarrow 2KOH$.$KOH$ is a strong base that dissociates comple

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$OH^{-}$

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(C) When $K_2O$ is added to water,it reacts to form potassium hydroxide: $K_2O + H_2O \rightarrow 2KOH$.$KOH$ is a strong base that dissociates completely in water to produce $K^{+}$ and $OH^{-}$ ions: $KOH \rightarrow K^{+} + OH^{-}$.The presence of a significant concentration of $OH^{-}$ ions makes the solution basic.Hence,option $C$ is correct.

When $K_2O$ is added to water,the solution becomes basic in nature because it contains a significant concentration of

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