When a balanced die is rolled,the probability | vedclass

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(B) The total number of possible outcomes when a balanced die is rolled is $S = \{1, 2, 3, 4, 5, 6\}$,so the total number of outcomes $n(S) = 6$.The m

Vedclass · Accepted Answer

$\frac{1}{3}$

Vedclass · Answer

(B) The total number of possible outcomes when a balanced die is rolled is $S = \{1, 2, 3, 4, 5, 6\}$,so the total number of outcomes $n(S) = 6$.The multiples of $3$ present on the faces of the die are $3$ and $6$.Let $E$ be the event of getting a multiple of $3$. Then $E = \{3, 6\}$,so the number of favorable outcomes $n(E) = 2$.The probability $P(E)$ is given by the formula $P(E) = \frac{n(E)}{n(S)}$.$P(E) = \frac{2}{6} = \frac{1}{3}$.Therefore,the probability of getting a multiple of $3$ is $\frac{1}{3}$.

When a balanced die is rolled,the probability of getting a multiple of $3$ on it is $\ldots \ldots \ldots .$

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