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Question

(A) The brown compound of manganese is manganese dioxide $(MnO_2)$.When $MnO_2$ reacts with concentrated $HCl$,it produces chlorine gas $(Cl_2)$: $MnO

Vedclass · Accepted Answer

$A = MnO_2, B = Cl_2, C = NCl_3$

Vedclass · Answer

(A) The brown compound of manganese is manganese dioxide $(MnO_2)$.When $MnO_2$ reacts with concentrated $HCl$,it produces chlorine gas $(Cl_2)$: $MnO_2 + 4HCl \rightarrow MnCl_2 + 2H_2O + Cl_2$.Thus,$A = MnO_2$ and $B = Cl_2$.When excess chlorine gas reacts with ammonia $(NH_3)$,it forms nitrogen trichloride $(NCl_3)$,which is an explosive compound: $NH_3 + 3Cl_2 \rightarrow NCl_3 + 3HCl$.Thus,$C = NCl_3$.

When a brown compound of manganese $(A)$ is treated with $HCl$,it gives a gas $(B)$. The gas taken in excess,reacts with $NH_3$ to give an explosive compound $(C)$. Identify compounds $A$,$B$,and $C$.

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