When a brown compound of manganese (A) is tre | vedclass

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Question

(A) The brown compound of manganese is $MnO_2$ $(A)$. When $MnO_2$ reacts with $HCl$,it produces chlorine gas $(B)$:$MnO_2 (A) + 4 HCl \rightarrow MnC

Vedclass · Accepted Answer

$A=MnO_2, B=Cl_2, C=NCl_3$

Vedclass · Answer

(A) The brown compound of manganese is $MnO_2$ $(A)$. When $MnO_2$ reacts with $HCl$,it produces chlorine gas $(B)$:$MnO_2 (A) + 4 HCl \rightarrow MnCl_2 + 2 H_2O + Cl_2 (B)$When excess chlorine gas $(B)$ reacts with ammonia $(NH_3)$,it forms nitrogen trichloride $(C)$,which is an explosive compound:$3 Cl_2 (B) + NH_3 \rightarrow NCl_3 (C) + 3 HCl$Thus,the compounds $A$,$B$,and $C$ are $MnO_2$,$Cl_2$,and $NCl_3$ respectively.

When a brown compound of manganese $(A)$ is treated with $HCl$,it gives a gas $(B)$. The gas $(B)$ taken in excess reacts with $NH_3$ to give an explosive compound $(C)$. The compounds $A$,$B$ and $C$ are:

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