When a certain alkane is mixed with chlorine | vedclass

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Question

(D) The formation of only one monochloroalkane indicates that all hydrogen atoms in the alkane are equivalent. In $Neopentane$ $(2,2-dimethylpropane)$

Vedclass · Accepted Answer

Neopentane

Vedclass · Answer

(D) The formation of only one monochloroalkane indicates that all hydrogen atoms in the alkane are equivalent. In $Neopentane$ $(2,2-dimethylpropane)$,all $12$ hydrogen atoms are equivalent. When $Neopentane$ reacts with $Cl_2$ in the presence of ultraviolet light,it replaces any one of the equivalent hydrogen atoms to form $1-chloro-2,2-dimethylpropane$ as the only product. Therefore,the correct answer is $Neopentane$.

When a certain alkane is mixed with chlorine and irradiated with ultraviolet light,only one monochloroalkane is formed. This alkane is likely to be:

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