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(D) The magnetic force $F$ acting on a current-carrying conductor placed in a magnetic field is given by the formula $F = I L B \sin(	heta)$.Here,$I$

Vedclass · Accepted Answer

All of the above

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(D) The magnetic force $F$ acting on a current-carrying conductor placed in a magnetic field is given by the formula $F = I L B \sin(	heta)$.Here,$I$ is the electric current,$L$ is the length of the conductor within the magnetic field,$B$ is the magnetic field strength,and $	heta$ is the angle between the current direction and the magnetic field.Since the wire is placed perpendicular to the magnetic field,$	heta = 90^\circ$,and $\sin(90^\circ) = 1$.Therefore,the force $F = I L B$.This shows that the magnetic force is directly proportional to the electric current $(I)$,the length of the wire $(L)$,and the magnetic field strength $(B)$.Thus,all the given options are correct.

When a light,straight conducting wire is suspended perpendicular to a strong magnetic field and an electric current is passed through it,the magnetic force acting on it is proportional to which of the following?

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