When a point source of light is at a distance of $1 \ m$ from a photocell,the cut-off voltage is found to be $V$. If the same source is placed at $2 \ m$ distance from the photocell,the cut-off voltage will be

  • A
    $V$
  • B
    $V/2$
  • C
    $V/4$
  • D
    $V/\sqrt{2}$

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