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(D) The magnetic force on a charged particle is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$.$1$. If the velocity $\vec{v}$ is parallel or anti-para

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any one of $(1)$,$(2)$ and $(3)$

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(D) The magnetic force on a charged particle is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$.$1$. If the velocity $\vec{v}$ is parallel or anti-parallel to the magnetic field $\vec{B}$,then $\vec{v} 	imes \vec{B} = 0$,so $\vec{F} = 0$. The particle continues in a straight line.$2$. If the velocity $\vec{v}$ is perpendicular to the magnetic field $\vec{B}$,the force acts as a centripetal force,causing the particle to move in a circle.$3$. If the velocity $\vec{v}$ makes an angle $	heta$ (where $	heta 
eq 0^\circ, 90^\circ, 180^\circ$) with the magnetic field $\vec{B}$,the velocity component parallel to the field remains constant,while the perpendicular component causes circular motion. This results in a helical trajectory.Therefore,all three trajectories are possible depending on the angle between $\vec{v}$ and $\vec{B}$.

When a positively charged particle enters a uniform magnetic field with uniform velocity,its trajectory can be :
$(1)$ a straight line
$(2)$ a circle
$(3)$ a helix

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When a positively charged particle enters a uniform magnetic field with uniform velocity,its trajectory can be :$(1)$ a straight line$(2)$ a circle$(3)$ a helix