When an aqueous solution of copper $(II)$ sulphate is saturated with ammonia,the blue compound crystallises on evaporation. The formula of this blue compound is

  • A
    $[Cu(NH_3)_4]SO_4 \cdot H_2O$ (square planar)
  • B
    $[Cu(NH_3)SO_4]$ (tetrahedral)
  • C
    $[Cu(NH_3)_6]SO_4$ (octahedral)
  • D
    $[Cu(SO_4)(NH_3)_4]$ (octahedral)

Explore More

Similar Questions

The complex ion $[Cu(NH_3)_4]^{2+}$ is:

Difficult
View Solution

Match the following:
Column-$I$ Complex Column-$II$ Structure / Geometry / Property
$A$. $[Ni(CN)_4]^{2-}$ $I$. Tetrahedral / Paramagnetic
$B$. $[Ni(CO)_4]$ $II$. Tetrahedral / Diamagnetic
$C$. $[NiCl_4]^{2-}$ $III$. Square planar / Diamagnetic
The correct match is:

$EDTA^{4-}$ is the ethylenediaminetetraacetate ion. The total number of $N-Co-O$ bond angles in the $[Co(EDTA)]^{-}$ complex ion is:

An aqueous solution of $NiCl_{2}$ was heated with excess sodium cyanide in the presence of a strong oxidizing agent to form $[Ni(CN)_{6}]^{2-}$. The total change in the number of unpaired electrons on the metal centre is $.....$

$A$ complex involving $dsp^2$ hybridization has:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo