When an electron makes a transition from $n=4$ to $n=2$,the emitted line spectrum will be:

  • A
    first line of Lyman series
  • B
    first line of Paschen series
  • C
    second line of Balmer series
  • D
    second line of Paschen series

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Similar Questions

The difference in the wavelength between the maximum and minimum of Balmer series [Use $R_{H} = 1 \times 10^7 \ m^{-1}$]. (in $Å$)

The wave number of the first line in the Lyman series of a hydrogen atom is ($R$ is Rydberg's constant).

The spectral series of the hydrogen atom that lies in the visible region of the electromagnetic spectrum is:

The shortest wavelength in the Balmer series of a hydrogen atom is equal to the shortest wavelength in the Brackett series of a hydrogen-like atom of atomic number $Z$. The value of $Z$ is:

The ratio of the shortest wavelengths of Bracket and Balmer series of hydrogen atom is

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