When an inductance L and resistor R are conne | vedclass

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(B) Given: Voltage $V = 25 \ V$, Current $I = 0.5 \ A$, Phase angle $\phi = \frac{\pi}{3} = 60^{\circ}$.
First, calculate the total impedance $Z$ of t

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$25$

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(B) Given: Voltage $V = 25 \ V$, Current $I = 0.5 \ A$, Phase angle $\phi = \frac{\pi}{3} = 60^{\circ}$.
First, calculate the total impedance $Z$ of the $LR$ series circuit using Ohm's law: $Z = \frac{V}{I} = \frac{25}{0.5} = 50 \ \Omega$.
In an $LR$ series circuit, the relationship between resistance $R$ and impedance $Z$ is given by $R = Z \cos \phi$.
Substituting the values: $R = 50 	imes \cos 60^{\circ}$.
Since $\cos 60^{\circ} = \frac{1}{2}$, we get $R = 50 	imes \frac{1}{2} = 25 \ \Omega$.
Therefore, the value of $R$ is $25 \ \Omega$.

When an inductance $L$ and resistor $R$ are connected in series to $25 \ V$, $50 \ Hz$ supply, a current of $0.5 \ A$ flows in the circuit. The current lags behind in phase from applied voltage by $(\frac{\pi}{3})$ radian. The value of $R$ is $(\cos 60^{\circ} = \frac{1}{2})$ (in $\Omega$)

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