When aniline is treated with sodium nitrite and hydrochloric acid at $0\,^{\circ}C$,it gives:

Which of the following is an example of a symmetrical tertiary amine?

How will you carry out the following conversion?
$Aniline \rightarrow m-Bromonitrobenzene$

Match List-$I$ with List-$II$:
Benzenediazonium chloride $(C_6H_5N_2^+Cl^-)$ is reacted with reagents in List-$I$ to form products in List-$II$.
| List-$I$ (Reagent) | List-$II$ (Product) |
| :--- | :--- |
| $A$. Aniline $(C_6H_5NH_2)$ | $I$. Fluorobenzene $(C_6H_5F)$ |
| $B$. $HBF_4, \Delta$ | $II$. Benzonitrile $(C_6H_5CN)$ |
| $C$. $Cu, HCl$ | $III$. $p$-Aminoazobenzene $(C_6H_5-N=N-C_6H_4-NH_2)$ |
| $D$. $CuCN/KCN$ | $IV$. Chlorobenzene $(C_6H_5Cl)$ |
Choose the correct answer from the options given below:

Which of the following undergoes nitration fastest?

Which of the following reaction/s will not give $p-$aminoazobenzene?