When a number is divided by 12,the quotient i | vedclass

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(B) Let the first number be $x$ and the second number be $y$.According to the problem,when $x$ is divided by $12$,the result is $\frac{1}{4}$ of $y$.S

Vedclass · Accepted Answer

$200$

Vedclass · Answer

(B) Let the first number be $x$ and the second number be $y$.According to the problem,when $x$ is divided by $12$,the result is $\frac{1}{4}$ of $y$.So,$\frac{x}{12} = \frac{1}{4}y$.Multiplying both sides by $12$,we get $x = \frac{12}{4}y = 3y$.This implies $\frac{x}{y} = \frac{3}{1}$,so $x = 3y$.The percentage by which the first number $(x)$ is greater than the second number $(y)$ is given by the formula:$	ext{Percentage increase} = \frac{x - y}{y} 	imes 100 \%$.Substituting $x = 3y$:$	ext{Percentage increase} = \frac{3y - y}{y} 	imes 100 \% = \frac{2y}{y} 	imes 100 \% = 2 	imes 100 \% = 200 \%$.

When a number is divided by $12$,the quotient is $\frac{1}{4}$ of another number. By what percentage is the first number greater than the second number?

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