When burnt in excess of oxygen, sodium forms | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When sodium is burnt in excess of oxygen, it forms sodium peroxide $(Na_2O_2)$, so $X = Na_2O_2$. In $Na_2O_2$, the peroxide ion is $O_2^{2-}$, wh

Vedclass · Accepted Answer

$X$ is diamagnetic and $Y$ is paramagnetic in nature

Vedclass · Answer

(B) When sodium is burnt in excess of oxygen, it forms sodium peroxide $(Na_2O_2)$, so $X = Na_2O_2$. In $Na_2O_2$, the peroxide ion is $O_2^{2-}$, which has the electronic configuration $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^2$. Since all electrons are paired, $Na_2O_2$ is diamagnetic. When potassium is burnt in excess of oxygen, it forms potassium superoxide $(KO_2)$, so $Y = KO_2$. In $KO_2$, the superoxide ion is $O_2^-$, which has one unpaired electron in the $\pi^* 2p$ orbitals. Therefore, $KO_2$ is paramagnetic. Thus, $X$ is diamagnetic and $Y$ is paramagnetic.

When burnt in excess of oxygen, sodium forms a compound $X$ and potassium forms a compound $Y$. The magnetic natures of $X$ and $Y$ respectively are

Similar Questions

$NaHCO_3$ can be manufactured by Solvay's process but $K_2CO_3$ cannot be prepared because

In the given reaction,the oxide of sodium is .... $4Na + O_2 \to 2Na_2O$ and $Na_2O + H_2O \to 2NaOH$

Hydroxide of which alkali metal is used in the manufacture of soft soap?

Identify the compound which gives $CO_2$ more readily on heating.

Write balanced chemical equations for the reactions between:
$(a)$ $Na_{2}O_{2}$ and water
$(b)$ $KO_{2}$ and water
$(c)$ $Na_{2}O$ and $CO_{2}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module