When chloroform is hydrolysed with KOH,the fi | vedclass

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(B) The hydrolysis of chloroform $(CHCl_3)$ with aqueous $KOH$ proceeds as follows:$1$. $CHCl_3 + 3KOH \rightarrow CH(OH)_3 + 3KCl$$2$. The intermedia

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$HCOOK$

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(B) The hydrolysis of chloroform $(CHCl_3)$ with aqueous $KOH$ proceeds as follows:$1$. $CHCl_3 + 3KOH \rightarrow CH(OH)_3 + 3KCl$$2$. The intermediate product,methanetriol $(CH(OH)_3)$,is unstable and loses a water molecule to form formic acid $(HCOOH)$: $CH(OH)_3 \rightarrow HCOOH + H_2O$$3$. Since the medium is basic ($KOH$ is present),the formic acid reacts with $KOH$ to form potassium formate $(HCOOK)$: $HCOOH + KOH \rightarrow HCOOK + H_2O$Thus,the final product is potassium formate $(HCOOK)$.

When chloroform is hydrolysed with $KOH$,the final product is:

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