When concentrated sulphuric acid is added slo | vedclass

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Question

(A) The brown ring test is used to detect the presence of nitrate ions $(NO_3^-)$ in a solution.$1$. The nitrate ion reacts with concentrated sulphuri

Vedclass · Accepted Answer

$[Fe(H_2O)_5NO]SO_4$

Vedclass · Answer

(A) The brown ring test is used to detect the presence of nitrate ions $(NO_3^-)$ in a solution.$1$. The nitrate ion reacts with concentrated sulphuric acid $(H_2SO_4)$ to produce nitric acid $(HNO_3)$:$NO_3^- + H_2SO_4 	o HNO_3 + HSO_4^-$$2$. The nitric acid is then reduced by ferrous sulphate $(FeSO_4)$ to form nitric oxide $(NO)$:$2HNO_3 + 6FeSO_4 + 3H_2SO_4 	o 3Fe_2(SO_4)_3 + 2NO + 4H_2O$$3$. The nitric oxide $(NO)$ reacts with the remaining ferrous sulphate to form the brown complex:$[Fe(H_2O)_6]^{2+} + NO 	o [Fe(H_2O)_5NO]^{2+} + H_2O$The composition of the brown ring is $[Fe(H_2O)_5NO]SO_4$.

When concentrated sulphuric acid is added slowly to a solution of ferrous sulphate containing nitrate ion,a brown coloured ring is formed. The composition of the ring is

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$AgNO_3 \xrightarrow{\Delta} (W) + (X) + O_2$
$(X) + H_2O \longrightarrow HNO_2 + HNO_3$
$(W) + HNO_3 \longrightarrow Y + NO + H_2O$
$(Y) + Na_2S_2O_3(\text{excess}) \longrightarrow (Z) + NaNO_3$
Identify $(W)$ to $(Z)$.

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