When ethyl alcohol $({C_2}{H_5}OH)$ reacts with thionyl chloride,in the presence of pyridine,the product obtained is
- A$CH_3CH_2Cl + HCl$
- B$CH_3COCl + HCl + SO_2$
- C$CH_3CH_2Cl + H_2O + SO_2$
- D$C_2H_5Cl + HCl + SO_2$
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