When ethyl chloride and alcoholic KOH are hea | vedclass

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(A) The reaction between ethyl chloride $(CH_3CH_2Cl)$ and alcoholic $KOH$ is a dehydrohalogenation reaction. In this reaction,an elimination process

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$C_2H_4$

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(A) The reaction between ethyl chloride $(CH_3CH_2Cl)$ and alcoholic $KOH$ is a dehydrohalogenation reaction. In this reaction,an elimination process occurs where a hydrogen atom and a chlorine atom are removed from adjacent carbon atoms to form an alkene. The chemical equation for the reaction is: $CH_3CH_2Cl + KOH (	ext{alc.}) ightarrow CH_2=CH_2 + KCl + H_2O$. Thus,the product obtained is ethene $(C_2H_4)$.

When ethyl chloride and alcoholic $KOH$ are heated,the compound obtained is

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