When glycerol is treated with an excess of HI | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) When glycerol $(CH_2OH-CHOH-CH_2OH)$ is treated with an excess of $HI$,it first undergoes substitution to form $1,2,3$-triiodopropane.This unstabl

Vedclass · Accepted Answer

$2$-iodopropane

Vedclass · Answer

(D) When glycerol $(CH_2OH-CHOH-CH_2OH)$ is treated with an excess of $HI$,it first undergoes substitution to form $1,2,3$-triiodopropane.This unstable intermediate loses a molecule of $I_2$ to form allyl iodide $(CH_2=CH-CH_2I)$.Allyl iodide then reacts with $HI$ to form $1,2$-diiodopropane,which further loses $I_2$ to form propene $(CH_3-CH=CH_2)$.Finally,propene reacts with $HI$ according to Markovnikov's rule to yield $2$-iodopropane $(CH_3-CH(I)-CH_3)$ as the final product.

When glycerol is treated with an excess of $HI$,it produces:

Similar Questions

Which of these dehydrates most easily?

Which of the following is a tertiary allylic alcohol?

Methanol and ethanol are distinguished by the

The major product of the following reaction is:

Which of the following compounds is most reactive toward acid-catalyzed dehydration?

Vedclass Test Series

Exam Paper Generator

Online Exam Module