When radiation of 300 nm is shone on five me | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The energy of the incident radiation is calculated using the formula $E = \frac{hc}{\lambda}$.For $\lambda = 300 \ nm = 300 	imes 10^{-9} \ m$, $

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(D) The energy of the incident radiation is calculated using the formula $E = \frac{hc}{\lambda}$.For $\lambda = 300 \ nm = 300 	imes 10^{-9} \ m$, $E = \frac{6.626 	imes 10^{-34} \ J \cdot s 	imes 3 	imes 10^8 \ m/s}{300 	imes 10^{-9} \ m} \approx 6.626 	imes 10^{-19} \ J \approx 4.14 \ eV$.The work functions $(\Phi)$ of the metals are approximately: $Li \approx 2.5 \ eV$, $Mg \approx 3.7 \ eV$, $Ag \approx 4.3 \ eV$, $Cu \approx 4.7 \ eV$, and $K \approx 2.3 \ eV$.Photoelectric effect occurs when $E > \Phi$.Comparing the values, $Li, Mg,$ and $K$ have work functions less than $4.14 \ eV$.Thus, $3$ metals show the photoelectric effect.

When radiation of $300 \ nm$ is shone on five metals, namely $Li, Mg, Ag, Cu,$ and $K$, the number of metals that show the photoelectric effect is:

Similar Questions

In the hydrogen spectrum,the different lines of the Lyman series are present in the:

$A$ metal surface is exposed to solar radiation.

The energy of an electromagnetic radiation is $19.875 \times 10^{-13} \ erg$. What is its wave number in $cm^{-1}$? $(h = 6.625 \times 10^{-27} \ erg \ sec, c = 3 \times 10^{10} \ cm \ sec^{-1})$

Splitting of spectral lines when atoms are subjected to a strong electric field is called:

Which of the following travels with the speed of light?

Vedclass Test Series

Exam Paper Generator

Online Exam Module