When resonance is produced in a series LCR ci | vedclass

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(D) The impedance $(Z)$ of a series $LCR$ circuit is given by $Z = \sqrt{R^2 + (X_L - X_C)^2}$.At resonance,the inductive reactance $(X_L)$ equals the

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Impedance of the circuit is maximum.

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(D) The impedance $(Z)$ of a series $LCR$ circuit is given by $Z = \sqrt{R^2 + (X_L - X_C)^2}$.At resonance,the inductive reactance $(X_L)$ equals the capacitive reactance $(X_C)$,so $X_L - X_C = 0$.Therefore,the impedance becomes $Z = R$,which is the minimum possible value for the circuit.Since $Z$ is minimum,the current $I = V/Z$ is maximum.At resonance,the phase angle $\phi = 	an^{-1}((X_L - X_C)/R) = 0$,meaning the current is in phase with the applied voltage.The voltage across the capacitor is $V_C = I X_C = (V/R) X_C$. If $R$ is reduced,$I$ increases,so $V_C$ increases.Thus,the statement that the impedance is maximum is incorrect.

When resonance is produced in a series $LCR$ circuit,then which of the following is not correct?

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