When the current through an inductor is chang | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The induced emf $\varepsilon$ in an inductor is given by the formula $\varepsilon = -L \frac{di}{dt}$.Taking the magnitude, we have $L = \frac{|\v

Vedclass · Accepted Answer

$1.5$

Vedclass · Answer

(C) The induced emf $\varepsilon$ in an inductor is given by the formula $\varepsilon = -L \frac{di}{dt}$.Taking the magnitude, we have $L = \frac{|\varepsilon|}{\frac{di}{dt}}$.Given: Change in current $\Delta i = 6 \,A - 2 \,A = 4 \,A$, time interval $\Delta t = 2 \,s$, and induced emf $\varepsilon = 3 \,V$.The rate of change of current is $\frac{di}{dt} = \frac{\Delta i}{\Delta t} = \frac{4 \,A}{2 \,s} = 2 \,A/s$.Substituting these values into the formula:$L = \frac{3 \,V}{2 \,A/s} = 1.5 \,H$.

When the current through an inductor is changed from $2 \,A$ to $6 \,A$ in time $2 \,s$, the emf induced in it is $3 \,V$. Then the inductance of the inductor is (in $\,H$)

Similar Questions

$A$ current $I$ produces a magnetic flux $\phi$ per turn in a coil of $n$ turns. The self-inductance of the coil is $L$. The relation between them is:

The self-inductance of a solenoid is:

The current in self-inductance $L=40\; mH$ is to be increased uniformly from $1\; A$ to $11\; A$ in $4\; ms$. The $e.m.f.$ induced in the inductor during this process is ..... $V$.

The equivalent quantity of mass in electricity is . . . . . . .

Consider a solenoid carrying current supplied by a $DC$ source with a constant $emf$ containing an iron core inside it. When the core is pulled out of the solenoid,the change in current will:

Vedclass Test Series

Exam Paper Generator

Online Exam Module