(A) We know that the change in entropy is given by $\Delta S = \frac{q_{rev}}{T}$.Given that the quantity of heat $q_{rev}$ is the same in both cases,

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) We know that the change in entropy is given by $\Delta S = \frac{q_{rev}}{T}$.Given that the quantity of heat $q_{rev}$ is the same in both cases,we have $\Delta S_{1} = \frac{q_{rev}}{T_{1}}$ and $\Delta S_{2} = \frac{q_{rev}}{T_{2}}$.Since $T_{1} > T_{2}$,the denominator in the expression for $\Delta S_{1}$ is larger than the denominator in the expression for $\Delta S_{2}$.Therefore,$\Delta S_{1} < \Delta S_{2}$.

Class 11 Chemistry Thermodynamics 2 nd Law of thermodynamics and Entropy

Medium

When the same quantity of heat is absorbed by a system at two different temperatures $T_{1}$ and $T_{2}$,such that $T_{1} > T_{2}$,the changes in entropy are $\Delta S_{1}$ and $\Delta S_{2}$ respectively. Then:

KCET 2020 All KCET

A
$\Delta S_{1} < \Delta S_{2}$
B
$\Delta S_{1} = \Delta S_{2}$
C
$\Delta S_{1} > \Delta S_{2}$
D
$\Delta S_{2} < \Delta S_{1}$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

Thermodynamics

Subtopic

2 nd Law of thermodynamics and Entropy

Previous Year

KCET 2020 Paper All KCET years →

Which state functions are required to understand the second law of thermodynamics?

Easy

View Solution

In an isolated system,find the condition for a spontaneous reaction.

MediumAIIMS 2019

View Solution

Calculate the entropy change in $JK^{-1}$ for the reversible expansion of $5 \ mol$ of an ideal gas at $27 \ ^oC$ from $8 \ dm^3$ to $80 \ dm^3$.

Medium

View Solution

Enthalpy of vaporization of benzene is $+35.3 \ kJ \ mol^{-1}$ at its boiling point,$80^{\circ} C$. The entropy change in the transition of the vapour to liquid at its boiling point in $[J \ K^{-1} \ mol^{-1}]$ is

MediumKCET 2010

View Solution

Assertion : Water in liquid state is more stable than ice at room temperature.
Reason : Water in liquid form has higher entropy than ice.

EasyAIIMS 2006

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

When the same quantity of heat is absorbed by a system at two different temperatures $T_{1}$ and $T_{2}$,such that $T_{1} > T_{2}$,the changes in entropy are $\Delta S_{1}$ and $\Delta S_{2}$ respectively. Then:

Similar Questions

Which state functions are required to understand the second law of thermodynamics?

In an isolated system,find the condition for a spontaneous reaction.

Calculate the entropy change in $JK^{-1}$ for the reversible expansion of $5 \ mol$ of an ideal gas at $27 \ ^oC$ from $8 \ dm^3$ to $80 \ dm^3$.

Enthalpy of vaporization of benzene is $+35.3 \ kJ \ mol^{-1}$ at its boiling point,$80^{\circ} C$. The entropy change in the transition of the vapour to liquid at its boiling point in $[J \ K^{-1} \ mol^{-1}]$ is

Assertion : Water in liquid state is more stable than ice at room temperature.Reason : Water in liquid form has higher entropy than ice.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Assertion : Water in liquid state is more stable than ice at room temperature.
Reason : Water in liquid form has higher entropy than ice.