When zinc reacts with very dilute HNO_3,the o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When zinc reacts with very dilute $HNO_3$,it acts as a strong reducing agent and reduces the nitrogen in $HNO_3$ from its $+5$ oxidation state to

Vedclass · Accepted Answer

$+5$ to $-3$

Vedclass · Answer

(B) When zinc reacts with very dilute $HNO_3$,it acts as a strong reducing agent and reduces the nitrogen in $HNO_3$ from its $+5$ oxidation state to $-3$ in ammonium nitrate $(NH_4NO_3)$.The balanced chemical equation is:$4Zn_{(s)} + 10HNO_{3(aq)} \rightarrow 4Zn(NO_3)_{2(aq)} + NH_4NO_{3(aq)} + 3H_2O_{(l)}$In $HNO_3$,the oxidation state of $N$ is $+5$.In $NH_4NO_3$,the oxidation state of $N$ in the $NH_4^+$ ion is $-3$.

When zinc reacts with very dilute $HNO_3$,the oxidation state of nitrogen changes from

Similar Questions

The oxidation state of $I$ in $H_4IO_6^-$ is

What is the oxidation state of nitrogen in $N_3H$?

What is the oxidation state of $Fe$ in $Fe_3O_4$?

Arrange the following substances in the increasing order of the oxidation number of $Mn$: $MnCl_2, MnO_2, Mn(OH)_3, KMnO_4$.

In which of the following compounds is the oxidation state of nitrogen correctly represented?

Vedclass Test Series

Exam Paper Generator

Online Exam Module