Where will a body weigh more: 1 , km above th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The acceleration due to gravity $g$ at a height $h$ above the surface is given by $g_h = g(1 - 2h/R)$.The acceleration due to gravity $g$ at a dep

Vedclass · Accepted Answer

$1 \, km$ below the surface

Vedclass · Answer

(B) The acceleration due to gravity $g$ at a height $h$ above the surface is given by $g_h = g(1 - 2h/R)$.The acceleration due to gravity $g$ at a depth $d$ below the surface is given by $g_d = g(1 - d/R)$.For the same distance $h = d = 1 \, km$,we compare the reduction in gravity.At height $h$,the reduction is $2h/R$,while at depth $d$,the reduction is $d/R$.Since $2h/R > d/R$,the value of $g$ decreases more at height $h$ than at depth $d$.Therefore,the body will weigh more at a depth of $1 \, km$ below the surface of the earth.

Where will a body weigh more: $1 \, km$ above the surface of the earth or $1 \, km$ below the surface of the earth?

Similar Questions

What would be the effect on the weight of a body if the earth stopped rotating?

The weight of an object:

$A$ body of mass $10 \,kg$ is taken to the centre of the earth. What will be its mass there (in $,kg$)?

Amit buys a few grams of gold at the poles as per the instruction of one of his friends. He hands over the same when he meets him at the equator. Will the friend agree with the weight of gold bought? If not,why? [Hint: The value of $g$ is greater at the poles than at the equator.]

It is said that the mass of an object remains constant at all places,while its weight may change. Why?

Vedclass Test Series

Exam Paper Generator

Online Exam Module