Which allotropic form of carbon does not have | vedclass

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Question

(A) In $diamond$,each carbon atom is $sp^3$ hybridized and bonded to four other carbon atoms in a tetrahedral geometry,forming a rigid $3D$ network st

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diamond

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(A) In $diamond$,each carbon atom is $sp^3$ hybridized and bonded to four other carbon atoms in a tetrahedral geometry,forming a rigid $3D$ network structure. It does not contain any hexagonal rings.In $graphite$,carbon atoms are arranged in layers of hexagonal rings.In $fullerenes$ (like $C_{60}$),the structure consists of both hexagonal and pentagonal rings.Therefore,$diamond$ is the correct answer.

Which allotropic form of carbon does not have hexagonal rings in its structure?

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