Which among the following elements possesses one electron in the $4s$ orbital in its observed electronic configuration?

In a multielectron atom,which of the following orbitals described by three quantum numbers will have the same energy in the absence of electric and magnetic fields?
$A: n=1, \ell=0, m_{\ell}=0$
$B: n=2, \ell=0, m_{\ell}=0$
$C: n=2, \ell=1, m_{\ell}=1$
$D: n=3, \ell=2, m_{\ell}=1$
$E: n=3, \ell=2, m_{\ell}=0$
Choose the correct answer from the options given below:

Which of the following orbitals has/have zero probability of finding the electron in the $xy$ plane?

The electronic configuration of chromium ($Cr$,$Z=24$) is:

The quantum numbers $n$ and $l$ for four electrons are given as: $(1) \, n = 4, l = 1; \, (2) \, n = 4, l = 0; \, (3) \, n = 3, l = 2; \, (4) \, n = 3, l = 1$. Arrange them in increasing order of their energy.

What is the difference between the $2s$ orbital of hydrogen and the $2s$ orbital of other multi-electron atoms?