Class 11Chemistry1 Organic Chemistry: Classification and Nomenclature of Organic CompoundsBonding and hybridisation in organic compounds
EasyWhich among the following possesses a $sp$ carbon in its structure?
- A$CH_2=CCl-CH=CHBr$
- B$CBr_4$
- C$CH_2=C=CH_2$
- D$C_6H_5-CCl_3$
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Similar Questions
What is the number of $sp^3$ hybridized carbon atoms in $HO(CH_2)_2CH(CH_3)_2$?
The number of $sp^{3}$ hybridised carbons in an acyclic neutral compound with molecular formula $C_{4}H_{5}N$ is.
How many $(i)$ $sp^{2}$ hybridised carbon atoms and $(ii)$ $\pi$ bonds are present in the following compound?
MediumNEET 2020
View SolutionIn the compound $^1CH_2 = ^2CH - ^3CH_2 - ^4CH_2 - ^5C \equiv ^6CH$, the $C_2 - C_3$ bond is of which type?
What is the type of hybridisation of each carbon atom in the following compounds?
$(a)$ $CH_{3}Cl$
$(b)$ $(CH_{3})_{2}CO$
$(c)$ $CH_{3}CN$
$(d)$ $HCONH_{2}$
$(e)$ $CH_{3}CH=CHCN$
$(a)$ $CH_{3}Cl$
$(b)$ $(CH_{3})_{2}CO$
$(c)$ $CH_{3}CN$
$(d)$ $HCONH_{2}$
$(e)$ $CH_{3}CH=CHCN$
Medium
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