Which carbon atom (numbered from 1' to 5') of | vedclass

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(C) $1$. Ribose is a pentose sugar with the formula $C_5H_{10}O_5$, where each carbon atom is attached to a hydroxyl $(-OH)$ group.$2$. Deoxyribose is

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$2'$

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(C) $1$. Ribose is a pentose sugar with the formula $C_5H_{10}O_5$, where each carbon atom is attached to a hydroxyl $(-OH)$ group.$2$. Deoxyribose is a derivative of ribose with the formula $C_5H_{10}O_4$.$3$. The prefix 'deoxy' indicates the removal of an oxygen atom.$4$. In deoxyribose, the hydroxyl group at the $2'$ position of the ribose sugar is replaced by a hydrogen atom, meaning the oxygen atom is missing at the $2'$ carbon.$5$. Therefore, the $2'$ carbon atom lacks the oxygen atom.

Which carbon atom (numbered from $1'$ to $5'$) of ribose lacks the oxygen to form deoxyribose ?

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