Which compound on reductive ozonolysis produc | vedclass

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(C) Reductive ozonolysis of an alkene involves the cleavage of the $C=C$ double bond to form carbonyl compounds ($aldehydes$ or $ketones$).If the alke

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$CH_2=C=CH_2$

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(C) Reductive ozonolysis of an alkene involves the cleavage of the $C=C$ double bond to form carbonyl compounds ($aldehydes$ or $ketones$).If the alkene has a terminal $CH_2$ group (i.e.,$R-CH=CH_2$),it produces formaldehyde $(HCHO)$.If the alkene has a $C=C$ bond where the carbon is bonded to two other groups,it produces ketones.Specifically,for allene $(CH_2=C=CH_2)$,the central carbon atom is bonded to two double bonds. Upon ozonolysis,the central carbon is oxidized to $CO_2$ because it is bonded to two terminal $CH_2$ groups which become formaldehyde $(HCHO)$.The reaction is: $CH_2=C=CH_2 + 2O_3$ $ightarrow 	ext{ozonide intermediate}$ $\xrightarrow{Zn/H_2O} 2HCHO + CO_2$.Thus,$CH_2=C=CH_2$ produces $CO_2$.

Which compound on reductive ozonolysis produces at least one mole of $CO_2$?

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