Which free radical from the following is leas | vedclass

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(A) The stability of a carbon free radical $(CFR)$ is directly proportional to the number of $\alpha$-hydrogen atoms present due to hyperconjugation.$

Vedclass · Accepted Answer

$\dot{C}H_3$

Vedclass · Answer

(A) The stability of a carbon free radical $(CFR)$ is directly proportional to the number of $\alpha$-hydrogen atoms present due to hyperconjugation.$1. \dot{C}H_3$ (methyl radical): $0 \ \alpha-H$$2. CH_3-\dot{C}H_2$ (ethyl radical): $3 \ \alpha-H$$3. (CH_3)_2\dot{C}H$ (isopropyl radical): $6 \ \alpha-H$$4. (CH_3)_3\dot{C}$ (tert-butyl radical): $9 \ \alpha-H$Since the stability order is $(CH_3)_3\dot{C} > (CH_3)_2\dot{C}H > CH_3-\dot{C}H_2 > \dot{C}H_3$,the methyl radical $\dot{C}H_3$ is the least stable.

Which free radical from the following is least stable?

Similar Questions

Define carbocation,carbanion,and free radical.

Consider the following statements. Of these statements:
$(I) \ CH_3O-CH_2^+$ is more stable than $CH_3-CH_2^+$
$(II) \ Me_2CH^+$ is more stable than $CH_3-CH_2-CH_2^+$
$(III) \ CH_2=CH-CH_2^+$ is more stable than $CH_3-CH_2-CH_2^+$
$(IV) \ CH_2=CH^+$ is more stable than $CH_3-CH_2^+$

The shape of a carbonium ion (carbocation) is:

Identify the correct order of stability for carbocations.

In a carbonium ion,the carbon atom bearing the positive charge is in the:

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