Which from the following statements about [Co | vedclass

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(C) In $[Co(NH_3)_6]^{3+}$,the oxidation state of cobalt is $+3$. The valence shell electronic configuration of $Co^{3+}$ $(3d^6)$ is represented as:

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It is a high spin complex.

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(C) In $[Co(NH_3)_6]^{3+}$,the oxidation state of cobalt is $+3$. The valence shell electronic configuration of $Co^{3+}$ $(3d^6)$ is represented as: $3d$ ($4$ unpaired electrons),$4s$ (empty),$4p$ (empty).Since $NH_3$ is a strong field ligand,it causes pairing of electrons in the $3d$ orbitals.After pairing,the configuration becomes $t_{2g}^6 e_g^0$,meaning all electrons are paired.This makes the complex diamagnetic and a low spin complex.Therefore,the statement that it is a high spin complex is incorrect.

List-$I$	List-$II$
$A. K_2[Ni(CN)_4]$	$I. sp^3$
$B. [Ni(CO)_4]$	$II. sp^3d^2$
$C. [Co(NH_3)_6]Cl_3$	$III. dsp^2$
$D. Na_3[CoF_6]$	$IV. d^2sp^3$

Which from the following statements about $[Co(NH_3)_6]^{3+}$ complex is $NOT$ correct?

Similar Questions

Match List-$I$ with List-$II$:

List-$I$ List-$II$

$A. K_2[Ni(CN)_4]$ $I. sp^3$

$B. [Ni(CO)_4]$ $II. sp^3d^2$

$C. [Co(NH_3)_6]Cl_3$ $III. dsp^2$

$D. Na_3[CoF_6]$ $IV. d^2sp^3$

Choose the correct answer from the options given below:

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