Which gas shows real behavior?

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(C) An ideal gas follows the equation $PV = nRT$. We check which of the given options follows this equation. The option that does not follow this equa

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$1 \ mol \ NH_3$ at $300 \ K$ and $1 \ atm$ occupies volume $22.4 \ L$

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(C) An ideal gas follows the equation $PV = nRT$. We check which of the given options follows this equation. The option that does not follow this equation represents real gas behavior.$A)$ For $O_2$: $P = 1 \ atm$,$V = 11.2 \ L$,$n = \frac{16}{32} = 0.5 \ mol$,$T = 273 \ K$,$R = 0.0821 \ atm \ L \ K^{-1} \ mol^{-1}$.$PV = 1 	imes 11.2 = 11.2$.$nRT = 0.5 	imes 0.0821 	imes 273 \approx 11.2$.Since $PV = nRT$,it shows ideal behavior.$B)$ For $H_2$: $P = 24.63 \ atm$,$V = 0.5 \ L$,$n = \frac{1}{2} = 0.5 \ mol$,$T = 300 \ K$.$PV = 24.63 	imes 0.5 = 12.315$.$nRT = 0.5 	imes 0.0821 	imes 300 = 12.315$.Since $PV = nRT$,it shows ideal behavior.$C)$ For $NH_3$: $P = 1 \ atm$,$V = 22.4 \ L$,$n = 1 \ mol$,$T = 300 \ K$.$PV = 1 	imes 22.4 = 22.4$.$nRT = 1 	imes 0.0821 	imes 300 = 24.63$.Since $PV 
eq nRT$,it shows real gas behavior.$D)$ For $CO_2$: $P = 1 \ atm$,$V = 5.6 \ L$,$n = \frac{11}{44} = 0.25 \ mol$,$T = 273 \ K$.$PV = 1 	imes 5.6 = 5.6$.$nRT = 0.25 	imes 0.0821 	imes 273 \approx 5.6$.Since $PV = nRT$,it shows ideal behavior.

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