Which has the highest value of ionic radius?

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Question

(C) The number of electrons in the given ions are:$O^{2-} = 8 + 2 = 10$ electrons$F^{-} = 9 + 1 = 10$ electrons$B^{3+} = 5 - 3 = 2$ electrons$Li^{+} =

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$O^{2-}$

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(C) The number of electrons in the given ions are:$O^{2-} = 8 + 2 = 10$ electrons$F^{-} = 9 + 1 = 10$ electrons$B^{3+} = 5 - 3 = 2$ electrons$Li^{+} = 3 - 1 = 2$ electronsFor isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number) increases.Comparing $O^{2-}$ (atomic number $Z = 8$) and $F^{-}$ (atomic number $Z = 9$):Since $O^{2-}$ has a lower nuclear charge than $F^{-}$,it has a larger ionic radius.Therefore,$O^{2-}$ has the highest ionic radius among the given options.

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