Which ion has tetrahedral geometry:

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Question

(C) $1$. In $[Fe(CO)_5]$,the geometry is trigonal bipyramidal ($sp^3d$ hybridization).$2$. In $[Co(NH_3)_6]^{2+}$,the geometry is octahedral ($d^2sp^3

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$[NiCl_4]^{2-}$

Vedclass · Answer

(C) $1$. In $[Fe(CO)_5]$,the geometry is trigonal bipyramidal ($sp^3d$ hybridization).$2$. In $[Co(NH_3)_6]^{2+}$,the geometry is octahedral ($d^2sp^3$ or $sp^3d^2$ hybridization).$3$. In $[NiCl_4]^{2-}$,$Ni^{2+}$ has a $d^8$ configuration. $Cl^-$ is a weak field ligand,so it does not cause pairing. The hybridization is $sp^3$,resulting in a tetrahedral geometry.$4$. In $[Ni(CN)_4]^{2-}$,$Ni^{2+}$ has a $d^8$ configuration. $CN^-$ is a strong field ligand,causing pairing. The hybridization is $dsp^2$,resulting in a square planar geometry.Therefore,the correct option is $C$.

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