Which ion has the highest magnetic moment (on | vedclass

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(A) The magnetic moment (spin-only) is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.$1$. For

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$Fe^{3+}$

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(A) The magnetic moment (spin-only) is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.$1$. For $Fe^{3+}$ $(Z=26)$: Electronic configuration is $[Ar] 3d^5$. Number of unpaired electrons $(n)$ = $5$.$2$. For $Cr^{3+}$ $(Z=24)$: Electronic configuration is $[Ar] 3d^3$. Number of unpaired electrons $(n)$ = $3$.$3$. For $Co^{3+}$ $(Z=27)$: Electronic configuration is $[Ar] 3d^6$. Number of unpaired electrons $(n)$ = $4$.$4$. For $Ti^{3+}$ $(Z=22)$: Electronic configuration is $[Ar] 3d^1$. Number of unpaired electrons $(n)$ = $1$.Since $Fe^{3+}$ has the highest number of unpaired electrons $(n=5)$,it has the highest magnetic moment.

Which ion has the highest magnetic moment (only spin)?

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