Which of the following is NOT obtained when m | vedclass

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Question

(A) The hydrolysis of metal carbides yields specific hydrocarbons based on the carbon species present in the carbide lattice.$Al_4C_3$ is a methanide,

Vedclass · Accepted Answer

$Al_4C_3 + H_2O \longrightarrow CH \equiv CH$

Vedclass · Answer

(A) The hydrolysis of metal carbides yields specific hydrocarbons based on the carbon species present in the carbide lattice.$Al_4C_3$ is a methanide,which reacts with water to produce methane: $Al_4C_3 + 12H_2O \longrightarrow 4Al(OH)_3 + 3CH_4$.$CaC_2$ is an acetylide,which produces acetylene: $CaC_2 + 2H_2O \longrightarrow Ca(OH)_2 + C_2H_2$.$Mg_2C_3$ is an allylide,which produces propyne: $Mg_2C_3 + 4H_2O \longrightarrow 2Mg(OH)_2 + CH_3C \equiv CH$.$Be_2C$ is a methanide,which produces methane: $Be_2C + 4H_2O \longrightarrow 2Be(OH)_2 + CH_4$.Therefore,the reaction in option $A$ is incorrect as it produces methane,not acetylene.

List-$I$	List-$II$
$A$. Chlorophyll	$I$. $Na_2CO_3$
$B$. Soda ash	$II$. $CaSO_4$
$C$. Dentistry,Ornamental work	$III$. $Mg^{2+}$
$D$. Used in white washing	$IV$. $Ca(OH)_2$

Which of the following is $NOT$ obtained when metal carbides react with $H_2O$?

Similar Questions

Match List-$I$ with List-$II$.

List-$I$ List-$II$

$A$. Chlorophyll $I$. $Na_2CO_3$

$B$. Soda ash $II$. $CaSO_4$

$C$. Dentistry,Ornamental work $III$. $Mg^{2+}$

$D$. Used in white washing $IV$. $Ca(OH)_2$

Choose the correct answer from the options given below:

Assertion : $Al(OH)_3$ is insoluble in $NH_4OH$ but soluble in $NaOH$.
Reason : $NaOH$ is a strong alkali.

Compare the alkali metals and alkaline earth metals with respect to $(i)$ ionization enthalpy,$(ii)$ basicity of oxides,and $(iii)$ solubility of hydroxides.

Select the correct statement$(s)$.

Which of the following statements is not correct?

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