Which is the correct increasing order of atom | vedclass

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(A) Atomic radius decreases across a period (from left to right) and increases down a group.$Na$ $(Z=11)$ and $Mg$ $(Z=12)$ belong to the $3^{rd}$ per

Vedclass · Accepted Answer

$Mg < Na < K < Rb$

Vedclass · Answer

(A) Atomic radius decreases across a period (from left to right) and increases down a group.$Na$ $(Z=11)$ and $Mg$ $(Z=12)$ belong to the $3^{rd}$ period,where $Mg$ is to the right of $Na$,so $Mg $Na$,$K$,and $Rb$ belong to Group $1$. The order of atomic radii down the group is $Na Combining these,we compare the periods: $Mg$ ($3^{rd}$ period) is smaller than $Na$ ($3^{rd}$ period),and $Na$ is smaller than $K$ ($4^{th}$ period),which is smaller than $Rb$ ($5^{th}$ period).Thus,the correct increasing order is $Mg < Na < K < Rb$.

Which is the correct increasing order of atomic radii of $Na, K, Mg, Rb$?

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Assertion $(A)$: The ionic radii of $Na^{+}$ and $F^{-}$ are same.
Reason $(R)$: Both $Na^{+}$ and $F^{-}$ are isoelectronic species.
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