(D) Reducing power is inversely proportional to the standard reduction potential $(E^\circ)$. The lower (more negative) the $E^\circ$ value,the strong

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(D) Reducing power is inversely proportional to the standard reduction potential $(E^\circ)$. The lower (more negative) the $E^\circ$ value,the stronger the reducing agent. Given standard reduction potentials: $E^\circ_{Ag^{+}/Ag} = 0.80 \ V$ $E^\circ_{Hg^{2+}/Hg} = 0.79 \ V$ $E^\circ_{Cr^{3+}/Cr} = -0.74 \ V$ $E^\circ_{Mg^{2+}/Mg} = -2.37 \ V$ Comparing these values,the increasing order of reducing power is: $Ag < Hg < Cr < Mg$.

Class 12 Chemistry Electrochemistry Electrode potential and ECell

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Which is the increasing order of reducing power of the following metals on the basis of standard electrode potential? $Ag^{+}/Ag = 0.80 \ V$,$Mg^{2+}/Mg = -2.37 \ V$,$Hg^{2+}/Hg = 0.79 \ V$,$Cr^{3+}/Cr = -0.74 \ V$

GSEB 2020 All GSEB

A
$Mg < Cr < Hg < Ag$
B
$Cr < Mg < Ag < Hg$
C
$Hg < Ag < Mg < Cr$
D
$Ag < Hg < Cr < Mg$

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Electrode potential and ECell

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EasyTS EAMCET 2022

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The electrode potentials for $Cu^{2+}_{(aq)} + e^- \rightarrow Cu^{+}_{(aq)}$ and $Cu^{+}_{(aq)} + e^- \rightarrow Cu_{(s)}$ are $+0.15 \ V$ and $+0.50 \ V$ respectively. The value of $E^o_{Cu^{2+}/Cu}$ will be $........ \ V$.

AIPMT 2011

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What is the $e.m.f.$ of the cell in $V$?
$Cr | Cr^{3+} (1.0 \ M) || Co^{2+} (1.0 \ M) | Co$
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Medium

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Given the following standard electrode potentials:
$Cu^{+2} + 2e^{-} \to Cu$,$E^{o} = X_{1}$
$Cu^{+} + e^{-} \to Cu$,$E^{o} = X_{2}$
Calculate the standard electrode potential $E^{o}$ for the reaction: $Cu^{+2} + e^{-} \to Cu^{+}$

Difficult

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The $EMF$ of a cell whose half-cell reactions are given below is .......... $V$.
$Mg^{2+} + 2e^- \to Mg_{(s)}; E^o = -2.37 \ V$
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Medium

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Which is the increasing order of reducing power of the following metals on the basis of standard electrode potential? $Ag^{+}/Ag = 0.80 \ V$,$Mg^{2+}/Mg = -2.37 \ V$,$Hg^{2+}/Hg = 0.79 \ V$,$Cr^{3+}/Cr = -0.74 \ V$

Similar Questions

Given $E^{\circ} Mn^{7+} / Mn^{2+} = 1.51 \ V$ and $E^{\circ} Mn^{4+} / Mn^{2+} = 1.23 \ V$. Calculate $E^{\circ} Mn^{7+} / Mn^{4+}$. (in $V$)

The electrode potentials for $Cu^{2+}_{(aq)} + e^- \rightarrow Cu^{+}_{(aq)}$ and $Cu^{+}_{(aq)} + e^- \rightarrow Cu_{(s)}$ are $+0.15 \ V$ and $+0.50 \ V$ respectively. The value of $E^o_{Cu^{2+}/Cu}$ will be $........ \ V$.

What is the $e.m.f.$ of the cell in $V$?$Cr | Cr^{3+} (1.0 \ M) || Co^{2+} (1.0 \ M) | Co$Given: $E^{o}$ for $Cr^{3+} | Cr = -0.74 \ V$ and $Co^{2+} | Co = -0.28 \ V$

Given the following standard electrode potentials:$Cu^{+2} + 2e^{-} \to Cu$,$E^{o} = X_{1}$$Cu^{+} + e^{-} \to Cu$,$E^{o} = X_{2}$Calculate the standard electrode potential $E^{o}$ for the reaction: $Cu^{+2} + e^{-} \to Cu^{+}$

The $EMF$ of a cell whose half-cell reactions are given below is .......... $V$.$Mg^{2+} + 2e^- \to Mg_{(s)}; E^o = -2.37 \ V$$Cu^{2+} + 2e^- \to Cu_{(s)}; E^o = +0.34 \ V$ (in $V$)

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What is the $e.m.f.$ of the cell in $V$?
$Cr | Cr^{3+} (1.0 \ M) || Co^{2+} (1.0 \ M) | Co$
Given: $E^{o}$ for $Cr^{3+} | Cr = -0.74 \ V$ and $Co^{2+} | Co = -0.28 \ V$

Given the following standard electrode potentials:
$Cu^{+2} + 2e^{-} \to Cu$,$E^{o} = X_{1}$
$Cu^{+} + e^{-} \to Cu$,$E^{o} = X_{2}$
Calculate the standard electrode potential $E^{o}$ for the reaction: $Cu^{+2} + e^{-} \to Cu^{+}$

The $EMF$ of a cell whose half-cell reactions are given below is .......... $V$.
$Mg^{2+} + 2e^- \to Mg_{(s)}; E^o = -2.37 \ V$
$Cu^{2+} + 2e^- \to Cu_{(s)}; E^o = +0.34 \ V$ (in $V$)