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(A) The conversion of $1,3-$bisphosphoglyceric acid $(1,3-BPGA)$ to $3-$phosphoglyceraldehyde $(3-PGAL)$ is a reduction step in the Calvin cycle.This

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Triose phosphate dehydrogenase

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(A) The conversion of $1,3-$bisphosphoglyceric acid $(1,3-BPGA)$ to $3-$phosphoglyceraldehyde $(3-PGAL)$ is a reduction step in the Calvin cycle.This reaction is catalyzed by the enzyme $Triose\ phosphate\ dehydrogenase$.The reaction is represented as: $1,3-BPGA + 12 NADPH + 12 H^+ \xrightarrow{Triose\ phosphate\ dehydrogenase} 3-PGAL + 12 NADP^+ + 12 H_3PO_4$.

Which enzyme is involved in the conversion of $3-PGA$ to $3-PGAL$?

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